Question

If we have 0.06g of Al2(So4)3 how many Al3+ ions we have ?

Answer 1

Answer:

See below

Explanation:

We are given,

$Al_{2}\left( SO_{4}\right) _{3}$

Its molecular weight is 342 u. 1 mol of aluminium sulphate contains 2 Al3+ ions. Meaning, 342 grams of aluminium sulphate contains 2 mols of Al3+. Therefore, 0.06 grams of it will have,

$\begin{aligned}\dfrac {0.06\times 2}{342}\left( 6.022\times 10^{13}\right) \\ =2.11\times 10^{20}\end{aligned}$

ions in it.