Question

if we have tan(a)=√3 +1\√3 -1
a=??

Answer 1

• tan (a) = √3 + 1 / √3 - 1
• tan (a) = (√3 + 1)(√3 + 1) / (√3 - 1)(√3 + 1)
• tan (a) = 3 + 1 + 2√3 / 3 - 1
• tan (a) = 4 + 2√3 / 2
• tan (a) = 2(2 + √3) / 2
• tan (a) = 2 + √3
• tan (a) = 1 + 1 + tan 60
• tan (a) = tan 45 + tan 45 + tan 60
• a = 45 + 45 + 60
• a = 150