If we have the diagonals of a square how to find the area
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let the side be x
by pythagoras theorem,
side^2 + side^2 = diagonal^2
2side^2 = diagonal^2
side^2 = (diagonal^2)/2
area of square = (diagonal^2)/2
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i hope this will help you
-by ABHAY
by pythagoras theorem,
side^2 + side^2 = diagonal^2
2side^2 = diagonal^2
side^2 = (diagonal^2)/2
area of square = (diagonal^2)/2
_____________________________________________________________________________________________________________________________
i hope this will help you
-by ABHAY
Answered by
1
area of sqiare =1/2*d1*d2
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