If we increase the length by 2 units and the breadth by 2 units, then the area of rectangle is increased by 54 square units. Find the perimeter of the rectangle (in units).
Answers
Let the length of the rectangle be x units and the breadth be y units.
Area of the rectangle=length×breadth
=x×y=xy sq. units
From the given information, we have,
(x+2)×(y−2)=xy−28
and(x−1)×(y+2)=xy+33
(x+2)×(y−2)=xy−28
=>xy−2x+2y−4=xy−28
=>−2x+2y=−24
=>−x+y=−12
=>x=y+12....(i)
Also,(x−1)×(y+2)=xy+33
=>xy+2x−y−2=xy+33
=>2x−y=35....(ii)
Substituting equation (i) in equation (ii), we get,
2x−y=35
=>2(y+12)−y=35
=>2y+24−y=35
=>y=11
Substituting y=11 in equation (i), we get,
x=y+12
=>x=11+12
=>x=23
Therefore, length of rectangle =x=23 units
and breadth of rectangle =y=11 units
Area of rectangle =xy=23×11=253 square units
pls make it as brainlist
hey there,
Let length be l
breadth be b
therefore,
(l+2) *(b+2) = l*b+54
l*b+2l+2b+4=l*b+54
2l+2b=50
2(l+b)=50
perimeter of a rectangle =2(l+b)=50
~~~~~hope u understand it :-)~~~~~~