Question

If we keep a small ice cube eraser and rupee coin on a incliend planexplan top up the

Answer 1

Answer:

Ice cube is kept on inclined plane of angle 30∘and kinetic friction is 31.

Now balancing forces

mgsin30−μkmg=ma

gsin30−μkg=a

a=(sin30−μk)g

a=(21−31)g

a=(233−1)g

a=0.2113×9.8

a=2.07m/s2

a≈2m/s2

Thus acceleration of the block is 2m/s2.