Question

If we make a the subject of √(3a - 2) = √(a ⁄b)

a) a = 2b b)a = 3b + 1 c) a = 2b⁄(3b - 1) d) a = 5b – 1

Answer 1

Given:

$\sqrt{3a-2}=\sqrt{\dfrac{a}{b}}$

We have to find, the value of a is:

Solution:

∴ $\sqrt{3a-2}=\sqrt{\dfrac{a}{b}}$

Squaring both sides, we get

$\sqrt{3a-2}^2=\sqrt{\dfrac{a}{b}}^2$

⇒ 3a - 2 = $\dfrac{a}{b}$

⇒ 3a -  $\dfrac{a}{b}$ = 2

Taking a as common in L.H.S., we get

⇒ a(3 - $\dfrac{1}{b}$) = 2

⇒ a($\dfrac{3b-1}{b}$) = 2

⇒ a = $\dfrac{2b}{3b-1}$

∴ The value of a = $\dfrac{2b}{3b-1}$

Thus, the required "option c) $\dfrac{2b}{3b-1}$" is correct.