Question

if we place a metal plate between two charges than coulumbs force becomes​

Answer 1

Answer

$\underbrace{\bf F=\frac{k.q_1.q_2}{r^2}}$

Explanation

If we place a metal plate between two charges then

columb force becomes ,

$\bf F=\dfrac{k.q_1.q_2}{r^2}$

where ,

F denotes Columb force

k denotes proportionality constant = 9 × 10⁹ Nm²/C²

q₁ denotes charge 1

q₂ denotes charge 2

r denotes distance b/w two charges