Question

If we reduce 3x + 3y + 7 = 0 to the form Xcos alpha + Ysin alpha = p , then the value of p is​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Value of p = $\frac{7}{3\sqrt2}$

Step-by-step explanation:

According to this question

We have been given that,

3x + 3y + 7 = 0

Compression with $x\times cos(\alpha) +y\times cos(\alpha)$ = p

So, 3x + 3y = -7

- 3x - 3y = 7

Dividing by $\sqrt{(-3)^2 + (-3)^2}$ = $3\sqrt2$ in both sides

$\frac{-3x}{3\sqrt2} - \frac{-3y}{3\sqrt2}$ = $\frac{7}{3\sqrt2}$

Then p = $\frac{7}{3\sqrt2}$

Hence,  p = $\frac{7}{3\sqrt2}$