if we represent the distance above the ground by positive integer and that below the ground by negative integer the answer the following. an elevator descends into a mine shafts at the rate of 8 meter per minute what will be it position after one hour? if it begins to decend from 20 m above the ground what will be it's position after 30 minutes from the ground
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Hey the answer for your question is
8 meter per minute. So, after 1 hour, it will be at 8 multiplied by 60 = 480. Hence it is +480 meters. If it begins to move down at 20 meter, the after 30 minutes it be at 20 multiplied by 30 = 600 meters. Therefore, it's initial position is +480 - (-600) = - 120. Therefore it is 1wo meter below the ground.
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8 meter per minute. So, after 1 hour, it will be at 8 multiplied by 60 = 480. Hence it is +480 meters. If it begins to move down at 20 meter, the after 30 minutes it be at 20 multiplied by 30 = 600 meters. Therefore, it's initial position is +480 - (-600) = - 120. Therefore it is 1wo meter below the ground.
Hope this answer helps you. If it helped you then don't forget to mark it as a brainliest answer. Please. Thank you for your cooperation my friend.
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