Question

If we subtract 22 from three times a number, we get 68. Find the number. S2
Find a number which when multiplied by 7 and then reduced by 3 is equal to 53.
3t-
JV90
Sum of two numbers is 95. If one exceeds the other by 3. find the numbers.​

Answer 1

Answer:

1) that number is =x

x-3(22)=68

x=68-66=2

x=2

2)7x-3=53

7x=56

x=8

3)x+y=95

x=y+3

y+3+y=95

2y=92

y=92/2

y=46

Answer 2

Answer:

1.3N-22=68

3N=68+22

3N=90

N=90/3

N=30

2.7N-3=53

7N=56

N=56/7

N=8

3.x+y=95

x-y =3

adding above equations

x+y+x-y = 95+3

2x=98

x=98/2

×=49

substituting x value in any one of equation

49+y=95

y=95-49

y= 46

Therefore the two numbers are 49 and 46