Question

If we subtract 3 from a natural number and square the result, we will get 64. Then find the number.

Answer 1

Answer:

Let the natural number be x

ATQ

(x-3)^2=64

x-3= root64

(As when we transfer square to another side, we root the number.

If we used Identity (a+b)^2= a^2 + b^2 + 2ab then the question become quite difficult)

x-3= 8

x= 8+3

x=11

So, the natural number is 11