If we subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3, then the answer is
Answers
Answered by
3
Answer:
subtract 4a−7ab+3b+12 from 12a−9ab+5b−3
=12a−9ab+5b−3−(4a−7ab+3b+12)
=12a−9ab+5b−3−4a+7ab−3b−12
=8a−2ab+2b−15
Answered by
19
Answer: (12a-9ab+5b-3)-(4a-7ab+3b+12)
Answer:12a-9ab+5b-3-4a+7ab-3b-12
group like terms
12a-4a-9ab+7ab+5b-3b-3-12
8a-2ab+2b-15
:
Similar questions