Question

If we take 2.2g Of co2, 6.02 *10raised the power 21 atoms Of nitrogen and 0.03g atoms Of sulphur, than the molar ratio of c, n, and S atoms will be

Answer 1

Answer:

Answer:5 : 1 :3

Answer:5 : 1 :3Explanation: -

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 g

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / mol

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass}

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44}

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 mol

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number}

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number} = \frac{6.02x1021}{6.02x1023}

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number} = \frac{6.02x1021}{6.02x1023} = 0.01 mol

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number} = \frac{6.02x1021}{6.02x1023} = 0.01 mol0.03 gram atom of sulphur means 0.03 moles of sulphur.

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number} = \frac{6.02x1021}{6.02x1023} = 0.01 mol0.03 gram atom of sulphur means 0.03 moles of sulphur.Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

Answer:5 : 1 :3Explanation: -Mass of CO₂ = 2.2 gMolar mass of CO₂ = 44 g / molNumber of moles of CO₂ = \frac{Mass}{Molar mass} = \frac{2.2}{44} = 0.05 molNumber of atoms of nitrogen = 6.02 x 10²¹Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number} = \frac{6.02x1021}{6.02x1023} = 0.01 mol0.03 gram atom of sulphur means 0.03 moles of sulphur.Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03 = 5 : 1 : 3

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