Question

If we take 44 gm. of CO2 and 14 gm. of N2 as a mixture, what is the mole fraction

of CO2 in the mixture?​

Answer 1

$\huge\blue{Answer}$

The g-mol weight of CO2 is 44g, and the g-mol weight of N2 is 14gm.

Wo, we are mixing 1mol CO2 + 0.5 mol N2 = 1.5 mol total.

The CO2 molar fraction is 1/1.5 = 0.667

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Answer 2

The mole fraction  of $CO_2$ in the mixture is 0.67

Explanation:

Mole fraction of a substance is the ratio of the moles of that substance to the total number of moles present.

${\text {mole fraction of }}CO_2=\frac{\text{moles of }CO_2}{\text {moles of }CO_2+{\text {moles of }}N_2}$

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Thus ${\text{moles of }} CO_2=\frac{44g}{44g/mol}=1mol$

${\text{moles of }}N_2=\frac{14g}{28g/mol}=0.5mol$

${\text {mole fraction of }}CO_2=\frac{1}{1+0.5}$

${\text {mole fraction of }}CO_2=\frac{1}{1.5}=0.67$

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