Question

if we throw a ball upwards 100m its velocity =50m/s what is the position and time of it?​

Answer 1

Answer:

So the answer is 50 m/sec / 9.8 m/sec^2, or about 5.1 seconds. A ball is thrown vertically upward from the ground with an initial velocity of 50m/s.

Answer 2

Here,

• s (distance covered ) → 100 m.
• v → 50m/s
• u → 0 m/s
• a → ${10 \:ms^{-2}}$

To find :—

• † t (time)

We know that ,

$\color{red} \bold{s = ut + \frac{1}{2} a {t}^{2} }$

$\implies \: 100 = 0.t + \frac{1}{2} .10. {t}^{2}$

$\implies \: 100 = 5 {t}^{2}$

$\implies \: {t}^{2} = 20$

$\implies \: t \: = \sqrt{20}$

$\implies \boxed{\bold{ t \: = 2 \sqrt{5} \: \: sec}}$