Question

if we throw a body upwards with velocity 4m/s at what height does its kinetic energy reduce to half of its original value

Answer 1

Hope this might help

Answer 2

HIII

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GOOD QUESTION:-)

ANSWER



LET H BE THE HEIGHT WHERE THE KINETIC ENERGY IS 1/2 ITS ORIGINAL VALUE.
1/2 OF KINETIC ENERGY = POTENTIAL ENERGY AT THE POINT


A/Q,
1/2(1/2mv^2)=mgh
1/4×m×4×4=m×10×h [ taking g=10]
1/4×4×4=10×h
h= 4/10=0.4



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