Question

if we toss a coin two times .find the probability of getting (a)double head (b)at least on head (c)two tails (d)no head​

Answer 1

hii...
your solution is...
(a) sample space=4
favourable conditions=1
probability=1/4
(b) Sample space=4
favourable conditions=2
probability=2/4=1/2
(c) sample space=4
favourable conditions=1
probability=1/4
(d) sample space=4
favourable conditions=1
probability=1/4

Answer 2

Condition:Two coins are tossed at once

Outcomes:

HH,HT,TH and TT

Total number of outcomes:4

Probability=Favourable outcomes/Total outcomes

1. Let E be the emperical event

P(E)=1/4

→P(E)=0.25

The probability of having two heads at once is 0.25

2. Let E be the required event

P(E)=3/4

→P(E)=0.75

The probability of having at least one head is 0.75

3. Let P(E) be the emperical event

P(E)=1/4

→P(E)=0.25

The probability of having two tails is 0.25

4. Having two tails at once is same as no heads

So, the probability of having no heads is 0.25