If Weight of 10000 soldiers are
normally distributed and P( z>1.6)
where A (1.6) = 0.4452Then no. of
soldiers are
Answers
Given : Weight of 10000 soldiers are normally distributed
P( z>1.6)
To Find : no. of soldiers in z>1.6
Solution:
(z values mentioned in Question are with taking Mean = 0 and on right side are + ve and left side are - ve ) hence from - 0.50 to 0.50
P( z>1.6)
Z score is + ve
A( 1.6) = 0.4452
Hence 0.5 + 0.4452 = 0.9452 are below 1.6
Hence 1 - 0.9452 = 0.0548 are above 1.6
=> no. of soldiers are for z>1.6 = 10000 x 0.0548 = 548
548 soldiers are above P( z>1.6)
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