If weight of metal oxide is x g containing y g of oxygen the equivalent weight of metal will be
Answers
Answered by
35
Metal oxide = x gm
Oxygen = y gm
Metal = (x-y) gm
8 gm of oxygen will combine with 8(x-y)/y gm of metal
Equivalent mass of metal = 8(x-y)/y gm
Answered by
17
Hey there,
● Answer -
E = 8(x/y-1)
● Explaination -
Let E be equivalent mass of metal and m be no of equivalents reacted with oxygen.
One equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.
m(E+8) = x g ...(1)
No of equivalents reacted is given by -
m = y/8
Substituting this in eqn (1),
y/8 (E+8) = x
E+8 = 8x/y
E = 8x/y - 8
E = 8(x/y - 1)
Therefore, equivalent weight of metal is 8(x/y-1).
Hope this helps you...
● Answer -
E = 8(x/y-1)
● Explaination -
Let E be equivalent mass of metal and m be no of equivalents reacted with oxygen.
One equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.
m(E+8) = x g ...(1)
No of equivalents reacted is given by -
m = y/8
Substituting this in eqn (1),
y/8 (E+8) = x
E+8 = 8x/y
E = 8x/y - 8
E = 8(x/y - 1)
Therefore, equivalent weight of metal is 8(x/y-1).
Hope this helps you...
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