Question

if what is the principal if the interest is 40 for 1 year at 8 pcpa ?​

Answer 1

❍Simple Interest is 40 rupees for 1 year time at 8 percent rate.

How to do

❍ As given in the question Simple Interest is given 40 rupees and time is given 1 year and rate of interest is also given 8% and we are said to find Principal and as we know that for find Principal we use this formula Simple Interest is multiple of 100 by Time is multiple of Rate.So let's find!

As we know that

$\sf\boxed{Principal = {\dfrac{Simple\:Interest × 100}{Time × Rate}}}$

Now substitute the values

$\: \: \sf \implies \: principal = \frac{40 \times 100}{1 \times 8} \\ \\ \\ \: \: \sf\implies \: principal = 500 \: rupees$

$\therefore$Hence, Principal is 500 rupees.

Additional Information:

• Principal:The amount of money borrowed or lent out for a certain period is called Principal or sum.It is denoted by 'P'.
• Rate: The interest on Rs.100 for a year is called the Rate percent per annum.It is denoted by 'R'.
• Simple Interest: If the principal remains the same for the entire loan period or time(T) irrespective of the length of the period for which it is borrowed,then the interest is called Simple Interest.It is denoted by "S.I".

Note:Sometimes the rate of interest may be half yearly , quarterly, monthly etc.

Answer 2

★ The principal for ₹40 at the rate of 8% per annum for 1 year is ₹500.

Step-by-step explanation

Analysis -

‎ ‎ ‎ ‎ ‎ ‎We are asked to find the principal for 40 rupees at the rate of 8% per annum for 1 year.

Solution -

‎ ‎ ‎ ‎ ‎ ‎First let us know what does the term "simple interest" mean!

If the principal remains the same for the entire loan period, then the interest paid is called simple interest. Here,

• The money borrowed from an agency for a certain period of time is called the principal.
• The interest on ₹100 per annum is called the rate of interest.
• And the principal together with the interest is called the amount.

Formula for the computation of simple interest (S.I.), let 'P' be the principal, 'R' be the rate of interest and 'T' denotes the number of years.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \tt \pmb{S.I. = \frac{PTR}{100} }}}$

Now, by using this formula, we shall find the principal.

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\twoheadrightarrow$ S.I. = 40

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\twoheadrightarrow$ P = ?

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\twoheadrightarrow$ T = 1

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\twoheadrightarrow$ R = 8

On equating the values,

$\dashrightarrow{ \sf{40 = \dfrac{P \times 1 \times 8}{100} }} \\ \\ \dashrightarrow{ \sf{40 = \frac{P\times 8}{100} }} \\ \\ \dashrightarrow{ \sf{40 \times 100 = P \times 8}} \\ \\ \dashrightarrow{ \sf{4000 = P \times 8}} \\ \\ \dashrightarrow{ \sf{ \frac{ \cancel{4000}}{ \cancel8} = P }} \\ \\ \dashrightarrow \underline{ \boxed{ \bf \pmb{500/ \textsf{-} \: = \sf{P}}}}$

This is the required answer!

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