Question

If whole circle bearing of a line is 270 its reduced bearing is

Answer 1

$<b><u>$According to me the answer is W 90°

#Thank_uh

Answer 2

Answer:

A line's reduced bearing is. 4 90° W. if its full circle bearing is 270°.

Explanation:

How do you calculate the reduced bearing from the total bearing for the circle:

• Rules for converting from whole circle bearing to the reduced bearing
• when the Whole Circle Bearing (W.C.B.) ranges from 0 to 90 degrees. W.C.B = Reduced Bearing (R.B).
• W.C.B. is in the range of 90° to 180°. In cases when W.C.B. is between 180° and 270°, R.B. = (180° - W.C.B.). R.B = (W.C.B - 180°)
• when the W.C.B., or whole circle bearing, is between 270 and 360 degrees.

How do you determine a bearing's reduction:

• Rules for converting from whole circle bearing to the reduced bearing
• when the Whole Circle Bearing (W.C.B.) ranges from 0 to 90 degrees. W.C.B = Reduced Bearing (R.B).
• W.C.B. is in the range of 90° to 180°. R.B = (180° - W.C.B)
• W.C.B. is in the 180° to 270° range. R.B = (W.C.B - 180°)
• when the W.C.B., or whole circle bearing, is between 270 and 360 degrees.

hence A line's reduced bearing is. 4 90° W. if its full circle bearing is 270°.