if width of rectangle is24.7m and area is 550.81 sq m. what is the perimeter of the rectangle
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Answer:
OK, we’ve got a rectangular field with a perimeter of 118m; we’re asked to find the length of the field if it is 7m less than twice the width of the field.
Perimeter = 118m
2L + 2W = 118m
Length = (2W - 7m) We want to express L in terms of W, so that we are working with
one unknown, W.
2(2W - 7m) + 2W = 118m
4W - 14m + 2W = 118m
6W - 14m = 118m
6W = 118m + 14m
6W = 132m
W = 132m ÷ 6
W = 22m
∴ L = 2(22m) - 7m
L = 44m - 7m
L = 37m
Proof:
2L + 2W = 118m
2(37m) + 2(22m) = 118m
74m + 44m = 118m
118m = 118m
Proved: The field is 37m long and 22m wide
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0
Answer:
l×b=550.81
24.7×b=550.81
b=550.81/14.7
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