Question

If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J , then what is the electric potential at this point?



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Answer 1

Answer:

750 V

Step-by-step explanation:

V=W\Q

W=15J

Q=20mC or 0.02C

therefore,15J/0.02C

=750V

Answer 2

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The electric potential between two points is defined as the amount of work done by an external agent in moving a unit charge from one point to another.

Here one point is infinity.

Potential difference between two points = Work done / Quantity of charge in coulomb

Hence, P.D = W/q = 15 / (20 * 10-3) = 0.75 * 103 = 750 volts