Question

if work done in moving charge 20 mC from infinity to point O in an electric field is 15 J then what is the electric potential at that point

Answer 1

Explanation:

W = 15 J

Q= 20 mC (20×10-³C)

Usinɡ V =W∕Q

V = 15J/ 20×10-³C

V= 15×10³/20

V= 3×10³/4

V= 3000/4

V =750 or 7.5×10²V