If work
done is 3 time more than Charge then find the potential difference.
Answers
Answered by
0
Answer:
From relation of work done
W=
2
1
CV
2
, so W∝V
2
As V
2
=60−30=30V,V
1
=30−15=15V
Hence
W
1
W
2
=(
V
1
V
2
)
2
Or W
2
=(
15
30
)
2
W W
1
=W
W
2
=4W
Answered by
0
Answer:
From relation of work done
W=
2
1
CV
2
, so W∝V
2
As V
2
=60−30=30V,V
1
=30−15=15V
Hence
W
1
W
2
=(
V
1
V
2
)
2
Or W
2
=(
15
30
)
2
W W
1
=W
W
2
=4W
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