If x=0 and x= -1 are the root of the polynomial f(x)=2x^3-3x^2-3x^2+ax+b
find the value of a and b
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The values of a=-8&b=0 in the above equation.
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f(x) = 2x³ - 3x² + ax + b
given Zeroes are 0 and -1
Value of a and b
Given value of x = 0 and -1
»Putting x = 0 in the given polynomial
⇢ 2x³ - 3x² + ax + b = 0
⇢ 2×0³ - 3×0² +a×0 + b = 0
⇢ 0 -0 +0 + b = 0
»b = 0
✦ So, we get b = 0
,
»Putting value of x = -1 and b =0 in the given polynomial.
⇢ 2x³ - 3x² + ax + b = 0
⇢ 2×(-1)³ -3 ×(-1)² + a×(-1) + b = 0
⇢ 2× (-1) -3 ×1 -a +0 = 0
⇢ -2 -3 - a = 0
⇢ -5 - a = 0
⇢ - a = 5
» a = -5
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Value of a = -5 and b = 0
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