if x= 0 and x = -1 are the roots of the polyomial f(x) =2x power 3 - 3x power2 +ax+b
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ANSWER:
2X^3-3X^2+ax+b
1) when x=0
f(x)=2(0)^3-3(0)^2+a(0)+b
=0+b
b=0【given :root】
2) when x=-1,
f(x)=2(-1)^3-3(-1)^2+a(-1)+b
= -2-3-a+b
0 = -5-a+b
b= -5-a+b
Step-by-step explanation:
a=-5
substitute" a" value u will get b
value
try ur self u will get the answer and then tell me (^_^)(^_^)(^_-)
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