if x=0 and x=-1 are the zeroes of the polynomial f(x)=2x^3-3x^2+ax+b ,find the value of a and b
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Answer:
a=-5,b=0
Step-by-step explanation:
f(x)= 2x^3-3x^2+ax+b=0
f(0)= 20^3-30^2+a0+b=0
=0-0+0+b=0
=b=0
f(x)= 2x^3-3x^2+ax+b=0
f(-1)= 2(-1)^3-3(-1)^2+a(-1)+b=0
=-2-3-a+b=0
=-5-a+b=0
=-a+b =5
-a+b=5
-a+b=5
-a=5
a=-5
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