Question

If x=0 and x=2 are zeroes of the polynomial 2x^3-5x^2+ax+b, then find the value of a & b​

Answer 1

Answer:

Solution

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Correct options are A) and D)

If f(2)=2(2)

3

−5(2)

2

+a(2)+b=0

⇒16−20+2a+b=0⇒2a+b=4

⇒f(0)=2(0)

3

−5(0)

2

+a(0)+b=0

⇒b=0⇒2a=4⇒a=2,b=0

Answer 2

Answer:

The value of a and b is 2 and 0 respectively.

Step-by-step explanation:

Given that x = 2 and x = 0  are zeroes of the polynomial p(x)

= 2x^3-5x^2+ax+b, we have to find the value of a and b

As x = 2 and x = 0 are the zeroes polynomial therefore by remainder theorem

P(2)=0 and A(0)=0

P(0)=0

2(0)^3-5(0)^2+a(0)+b=0

a(2)=0

2(2)^3-5(2)^2+a(2)+b=0

16-20+2a+0=0

-4+2p=0

a=4/2=2

Hence, the value of a and b is 2 and 0 respectively

Hope this helps