If x=0 and x=2 are zeroes ofP (x)=2xpower3-5x ki power2 +ax+b, find the value of a and b
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for x=0, p(x)=2×0³-5×0²+a×0+b=0;[since, 0 is a zero of the given function.]
so, b=0.
for x=2, p(x)=2×2³-5×2²+2a+b=0[since, 2 is a zero of the given function.]
so, 16-20+2a+0=0[as, b=0]
=>-4+2a=0
=>2a=4
=>a=2
so, b=0.
for x=2, p(x)=2×2³-5×2²+2a+b=0[since, 2 is a zero of the given function.]
so, 16-20+2a+0=0[as, b=0]
=>-4+2a=0
=>2a=4
=>a=2
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