Question

If (x,0) is equidistant from (-4,6) and (14,-2) then find the x

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Hence, the value of $x$ is $5$.

Step-by-step explanation:

Concept:

Once we know the $x$ and $y$ coordinates, we can use the midpoint formula to determine a point's distance from other points. Then, we add both of the $y$ coordinates and divide by two after adding both of the $x$ coordinates.

Given:

It is provided that $(x,0)$ is equidistant from $(-4,6)$ and $(14,-2)$.

To find:

We have to find the value of $x$.

Solution:

We know that, Equidistant refers to a point that is the same distance apart from two specified points.

The equidistant mean $=1:1$

$P(x,0)$ is equidistant from $A(-4,6)$ and $B(14,-2)$

$P(x,0)=(\frac{x_{1} +x_{2} }{2} , \frac{y_{1} +y_{2} }{2})$

$P(x,0)=(\frac{-4 +14}{2} , \frac{6-2}{2})\\P(x,0)=(\frac{10}{2} , \frac{4}{2})\\P(x,0)=(5,2)$

Thus, the value of $x$ is $5$.

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