Question

If x=1/10 and y= -3/8 , then evaluate x+y and x-y.

Answer 1

Answer:

here,

x=1/10

y=-3/8

now,

x+y=

$\frac{1}{10} + \frac{ - 3}{8}$

$\frac{4 - 15}{40}$

$\frac{ - 11}{40}$

and,

x-y=

$\frac{1}{10} - \frac{ - 3}{8}$

$\frac{4 + 15}{40}$

$\frac{19}{40}$

Answer 2

Answer:

(x+y) = 1/10+ (-3/8)

= 1/10 - 3/8

= 4 - 15 / 40

= - 11 / 40

(x-y) = 1/10- ( - 3/8)

= 1/10 + 3/8

= 4+15/40

= 19/40