Math, asked by kseto5473, 1 day ago

If x= 1/10 and y= (-3)/8 then , evaluate (x+y),( x-y),( x ×y) and( x ÷y)

Answers

Answered by gifty1811
2
Answer:
(x+y)= 1/10+(-3/8)
=1/10-3/8
After L.C.M
= 1x4-3×5/40
=4-15/40
=-11/40 (ans)

(X-Y) =1/10-(-3/8)
=1/10+3/8
After L.C.M
=4+15/40
=19/40 (ans)

(X×y)= 1/10×(-3/8)
=-3/80 (ans)

(X÷y)= 1/10÷(-3/8)
Reciprocal
= 1/10×8/3
=4/15 (ans)
Answered by mumtazahmad194109
0

Answer:

Here,

x=1/10 and y=-3/8

then

1.(x+y)=1/10+(-3/8)

=4-15/40

=-11/40

2.(x-y)=1/10-(-3/8)

=4+15/40

=19/40

3.(x*y)=1/10*(-3/8)

=-3/80

4.(x/y)=1/10/(-3)/8

=1/10*8/(-3)

= -8/30)

= -4/15

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