If x +
1 - 13 then the value of x18 + x12 + x + 1 is:
Х
(A) O
(C) 2
(B) 1
(D) 3
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Answer = 0 (a)
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Step-by-step explanation:
Assuming the question as (x + 1/x) = 3 Squaring on both the sides we get (x + 1/x)2 = 32 x2 +(1/x2) + 2 = 9 ⇒ x2 +(1/x2) = 7 Now cubing on both the sides we get, [x2 +(1/x2)]3 = 73 LHs is in the form of (a + b)3 = a3 + b3 + 3ab (a + b) Hence [x2]3 + [(1/x2)]3 + 3 (x2) × (1/x2)[x2 +(1/x2)] = 343 ⇒ x6 + (1/x6) + 3 × 7 = 343 ⇒ x6 + (1/x6) + 21 = 343 ∴ x6 + (1/x6) = 343 − 21 = 322
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