Question

If x =1/(√2 +1) ; then (x + 1) equals to ?​

Answer 1

$\huge{\underline{\sf{\red{SOLUTION}}}}$

x= 1/(√2+1)

x=1/(√2+1) × (√2-1)/(√2-1)

x=(√2-1)/(√2)²-(1)²

x=√2-1/2-1

x=√2-1

Now putting the value :

x+1 = √2-1+1 = √2

Hope it helps ya ! (:

Answer 2

If x =1/(√2 +1) then (x + 1) equals to √2

Given :

$\displaystyle \sf{x = \frac{1}{ \sqrt{2} + 1 } }$

To find :

The value of x + 1

Solution :

Step 1 of 3 :

Write down the given expression

Here it is given that

$\displaystyle \sf{x = \frac{1}{ \sqrt{2} + 1 } }$

Step 2 of 3 :

Simplify the given expression

$\displaystyle \sf{x = \frac{1}{ \sqrt{2} + 1 } }$

$\displaystyle \sf{ \implies \: x = \frac{ \sqrt{2} - 1 }{ (\sqrt{2} + 1)( \sqrt{2} - 1) } }$

$\displaystyle \sf{ \implies \: x = \frac{ \sqrt{2} - 1 }{ {( \sqrt{2} )}^{2} - {1}^{2} } }$

$\displaystyle \sf{ \implies \: x = \frac{ \sqrt{2} - 1 }{ 2 - 1} }$

$\displaystyle \sf{ \implies \: x = \frac{ \sqrt{2} - 1 }{ 1} }$

$\displaystyle \sf{ \implies \: x = \sqrt{2} - 1 }$

Step 3 of 3 :

Find the value of x + 1

x + 1

= √2 - 1 + 1

= √2