If x=(1/2_/2-√3) find the value of x cube -2x square -7x +5
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value of x⁴ - 4x³ + x² + x - √3 = 2
it is given that, x = 2 + √3
⇒(x - 2) = √3
squaring both sides we get,
⇒(x - 2)² = (√3)²
⇒x² - 4x + 4 = 3
⇒x² - 4x + 1 = 0.......(1)
we have to find value of x⁴ - 4x³ + x² + x - √3
= x²(x² - 4x + 1) + x - √3
from equation (1) we get,
= x² × 0 + x - √3
= 0 + (2 + √3 ) - √3
= 2
hence, x⁴ - 4x³ + x² + x - √3 = 2
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