Question

If x = (1/2) (2p+2q-r), y = (1/3) (-p-2q+3r) and z=(1/5) (3p-4r+5q), then the value of 2x-3y-5z is:

Answer 1

2x - 3y - 5z= 2p+ 2q- r+ p+ 2q- 3r- 3p+ 4r- 5q= -q