If x=1/2-√3,find the value of x^2-2x^2- 7x+5
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Heya !!
X = 1/2-√3
Rationalizing the denominator 2-√3 .
X = 1/(2-√3 ) × ( 2 + √3 )/ ( 2 + √3 )
X = ( 2 + √3 )/ (2-√3 ) ( 2+√3 )
X = ( 2 + √3 ) / (2)² - (√3)²
X = ( 2 + √3 )
Therefore,
X² - 2X² - 7X + 5
=> -X² - 7X + 5
=> -(2+√3) - 7 ( 2 + √3 ) + 5
=> -2 - √3 - 14 - 7√3 + 5
=> -8√3 - 11. [ Answer ]
X = 1/2-√3
Rationalizing the denominator 2-√3 .
X = 1/(2-√3 ) × ( 2 + √3 )/ ( 2 + √3 )
X = ( 2 + √3 )/ (2-√3 ) ( 2+√3 )
X = ( 2 + √3 ) / (2)² - (√3)²
X = ( 2 + √3 )
Therefore,
X² - 2X² - 7X + 5
=> -X² - 7X + 5
=> -(2+√3) - 7 ( 2 + √3 ) + 5
=> -2 - √3 - 14 - 7√3 + 5
=> -8√3 - 11. [ Answer ]
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it will be it answer
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