Math, asked by deepSweethika, 1 year ago

If x=1/2-√3 find the value of x²-4x+1

Answers

Answered by ARoy
85
x=1/(2-√3)=(2+√3)/(2-√3)(2+√3)=(2+√3)/(4-3)=2+√3
∴,x²=(2+√3)²=4+4√3+3=7+4√3
∴, x²-4x+1=7+4√3-4(2+√3)+1
                  =7+4√3-8-4√3+1
                  =0 
Answered by ankitraj761
16

Answer:

x=1/(2-√3)=(2+√3)/(2-√3)(2+√3)=(2+√3)/(4-3)=2+√3

∴,x²=(2+√3)²=4+4√3+3=7+4√3

∴, x²-4x+1=7+4√3-4(2+√3)+1

                 =7+4√3-8-4√3+1

                 =0

Step-by-step explanation:

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