If x=1/2-√3 find the value of x²-4x+1
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Answered by
85
x=1/(2-√3)=(2+√3)/(2-√3)(2+√3)=(2+√3)/(4-3)=2+√3
∴,x²=(2+√3)²=4+4√3+3=7+4√3
∴, x²-4x+1=7+4√3-4(2+√3)+1
=7+4√3-8-4√3+1
=0
∴,x²=(2+√3)²=4+4√3+3=7+4√3
∴, x²-4x+1=7+4√3-4(2+√3)+1
=7+4√3-8-4√3+1
=0
Answered by
16
Answer:
x=1/(2-√3)=(2+√3)/(2-√3)(2+√3)=(2+√3)/(4-3)=2+√3
∴,x²=(2+√3)²=4+4√3+3=7+4√3
∴, x²-4x+1=7+4√3-4(2+√3)+1
=7+4√3-8-4√3+1
=0
Step-by-step explanation:
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