If x = 1/(2-√3), then find the value of 2x³- 2x² + 7x + 5
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x=1/(2-√3)
x=2+√3
2x^3-2x^2+7x+5
=2(2+√3)^3-2(2+√3)^2+7(2+√3)+5
=2(29-12√3)-2(7+2√3)+14+7√3+5
=58-24√3-14-4√3+14+7√3+5
=63-21√3
=7(9-3√3)
x=2+√3
2x^3-2x^2+7x+5
=2(2+√3)^3-2(2+√3)^2+7(2+√3)+5
=2(29-12√3)-2(7+2√3)+14+7√3+5
=58-24√3-14-4√3+14+7√3+5
=63-21√3
=7(9-3√3)
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