Math, asked by minecraftgang4321, 13 hours ago

if (x-1)²=8, then what is the value of (x+1)²​

Answers

Answered by farsanats96
0

Answer:

(x-1)²=8

x-1=√8

x=√8+1

then

(x+1)²=(√8+2)²

=8+4√8+4

=12+8√2

Answered by bjjadhav161969
0

Answer:

8

Step-by-step explanation:

x-1=root8

x=root 8 +1

thus,

x+1=root8 +1+1

(root 8 + 2)^2

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