Math, asked by khusboochoudhary2018, 5 days ago

if x=1+√2, find the value of (x-1/x)^3​

Answers

Answered by Aminaghulamali63
0

Answer:

Step-by-step explanation:

x=1-√2

(x-1/x)cube

x=1-√2 , 1/x=1/1-√2×1+√2/1+√2

1/x=1+√2/(1)-(√2)square

Since (a-b)(a+b)=square -bsquare

1/x=1+√2/1-2

1/x=1+√2/-1

1/x=-(1+√2)

(x-1/x)=(1-√2)-(-(1+√2)

(x-1/x)=1-√2+1+√2

(x-1/x)=2

(x-1/x)cube=2cube

(x-1/x)=8

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