if x=1+√2, find the value of (x-1/x)^3
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Answer:
Step-by-step explanation:
x=1-√2
(x-1/x)cube
x=1-√2 , 1/x=1/1-√2×1+√2/1+√2
1/x=1+√2/(1)-(√2)square
Since (a-b)(a+b)=square -bsquare
1/x=1+√2/1-2
1/x=1+√2/-1
1/x=-(1+√2)
(x-1/x)=(1-√2)-(-(1+√2)
(x-1/x)=1-√2+1+√2
(x-1/x)=2
(x-1/x)cube=2cube
(x-1/x)=8
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