Math, asked by prish123, 8 months ago

If x= (1-√2), find the value of (x-1/x) and (x-1/x)^3(cube)

plz explain me the answer..​

Answers

Answered by satyam2060
2

Answer:

hope it helps you

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Answered by anshu875
1

Answer:

x = 1-√2

so 1/x = 1/(1-√2)

now multiply with 1+√2 in numerator and denominator .

1/x = 1*(1+√2)/(1-√2)*(1+√2)

= (1+√2)/(1^2-√2^2)

= (1+√2) / (1-2)

=-(1+√2).

so x - 1/x = (1-√2) - (-(1+√2))

= 1-√2 - (-1-√2 )

=1-√2+1+√2

=2  First Ans

and (x-1/x)^3 = 2^3 = 8 second ans. :-P

Hope this helps

Step-by-step explanation:

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