If x= (1-√2), find the value of (x-1/x) and (x-1/x)^3(cube)
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x = 1-√2
so 1/x = 1/(1-√2)
now multiply with 1+√2 in numerator and denominator .
1/x = 1*(1+√2)/(1-√2)*(1+√2)
= (1+√2)/(1^2-√2^2)
= (1+√2) / (1-2)
=-(1+√2).
so x - 1/x = (1-√2) - (-(1+√2))
= 1-√2 - (-1-√2 )
=1-√2+1+√2
=2 First Ans
and (x-1/x)^3 = 2^3 = 8 second ans. :-P
Hope this helps
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