If x = -1/2 is a root of the quadratic polynomial equation 3x^2+kx-3=0 , then find the value of k
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Answer:
x = -1/2
3x² +kx -3=0
3(-1/2)²+k(-1/2)-3=0
3/4- k/2 - 3 =0
Take LCM 4
-2k - 8 =0
k = -4
Answered by
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Step-by-step explanation:
x = -1/2
3x² + kx - 3 =0
3(-1/2)² + k(-1/2) -3 = 0
3(1/4) -k/2 -3 = 0
3/4 - k/2 - 3 = 0
(3 - 2k - 12)/4 =0
3 - 2k - 12 = 0
-9 = 2k
k = -9/2
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