Math, asked by jobinmathew, 5 months ago

if x = – 1/2 is a solution of the Quadratic equation 3x²+ 2 Kx – 3 =0, find the value of k​

Answers

Answered by Gauri715
0

Answer:

hope it helps

Step-by-step explanation:

Since, x = – 1/2 is a solution of the Quadratic equation 3x²+ 2 Kx – 3 =0

here,

3x²+ 2 Kx - 3 =0

or, 3(-1/2)^2+ 2 K-1/2 – 3 =0

or, 3(1/4) - k - 3 =0

or, 3-12/4 - k = 0

or, 9/4 = k

so k = 9/4

Answered by rudebutcute
0

Answer:

given x = -1/2

3x^2 + 2kx - 3 = 0

put the value of x

3(-1/2)^2 + k(-1/2) - 3 = 0

3(1/4) - k - 3 = 0

3/4 - 3 = k

(3 - 12)/4 = k

k = -9/4

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