Question

if x=1/2 is a zero of polynomial of 2x²+kx-12 then find the value of k

Answer 1

Hope this answer may help you

Answer 2

Answer:

23

Step-by-step explanation:

Given : x=1/2 is a zero of polynomial of 2x²+kx-12

To Find : the value of k

Solution:

$2x^2+kx-12 =0$

$x=\frac{1}{2}$  is a zero of polynomial  $2x^2+kx-12 =0$

Substitute $x=\frac{1}{2}$ in the polynomial

$2(\frac{1}{2})^2+k(\frac{1}{2})-12 =0$

$\frac{1}{2}+k(\frac{1}{2})=12$

$k(\frac{1}{2})=\frac{23}{2}$

$k=\frac{23}{2} \times 2$

$k=23$

Hence the value of k is 23