Question

if x (1/2) is a zero of the polynomial f(x)=2x^3+ax^2-3x+2 ,find the value of a

Answer 1

Answer:

a =-3

Step-by-step explanation:

Let  f(x) = 2x^3+ax^2-3x+2

considering 1/2 as zero of the polynomial , f(1/2) = 2×(1/2)^3+a(1/2)^2-3(1/2)+2

f(x) =2×1/8+a/4-3/2+2 =0 (∵1/2 is a zero of the polynomial)

The  L.C.M  of the numbers in the denominators is 4

(1 -6+a+8)/4 =0

3+a=0

a=-3

Answer 2

Answer:

a = -3

Step-by-step explanation:

x = 1/2 is a zero of the given polynomial

f(1/2) = 2*(1/2)^3 + a*(1/2)^2 - 3*x + 2 = 0

           2/8 + a/4 - 3/2 + 2 = 0

           1/4 + a/4 - 6/4 + 8/4 = 0

           1 + a - 6 + 8 = 0

           a = -3