if x= -1/2 is a zero of the polynomial p(x)=2x^3+kx^2=11x-6,find the value of 'k'
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Answered by
0
Answer:
Solution
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Correct option is B)
Given,
f(x)=6x
3
−11x
2
+kx−20, and
x=
3
4
is root of f(x).
Then, f(
3
4
)=0.
Thus,
f(
3
4
)=6(
3
4
)
3
−11(
3
4
)
2
+k(
3
4
)−20=0
⇒6×
9.3
64
−11×
9
16
+
3
4k
−20=0
⇒128−176+12k−180=0
⇒12k+128−356=0
⇒12k=228
⇒k=19.
Step-by-step explanation:
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Answered by
0
Answer:
k=19
Step-by-step explanation:
x=-1/2
p(x)=2x^3+kx^2=11x-6
p(x)=2(-1/2)3+k(-1/2)2=11(-1/2)-6
p(x)=-3-k=33
k=19
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