Question

If x=1/2 is a zero of the polynomial
$p(x) = 8x ^{3} - ax ^{2} - x + 2$
Find the value of a​

Answer 1

Step-by-step explanation:

$\huge\bf\underline\green{answer}$

given,

1/2 is a zero of the polynomial.

to find,

value of a.

let's understand

given 1/2 is a zero of the polynomial i.e we can substitute 1/2 in place of x and equate it to zero.

$\huge\fcolorbox{black}{pink}{solution}$

p(x) = 8x³ -ax² -x +2 = 0

p(1/2) = 8(1/2)³ -a(1/2)²-1/2+2 = 0

8(1/8) - a(1/4) -1/2 +2 = 0

1 -a/4 -1/2 +2 = 0

4-a-4+8/4 = 0

-a+8 = 0

a = 8

Answer 2

Step-by-step explanation:

$\huge\bf\underline\green{answer}$

given,

1/2 is a zero of the polynomial.

to find,

value of a.

let's understand

given 1/2 is a zero of the polynomial i.e we can substitute 1/2 in place of x and equate it to zero.

$\huge\fcolorbox{black}{pink}{solution}$

p(x) = 8x³ -ax² -x +2 = 0

p(1/2) = 8(1/2)³ -a(1/2)²-1/2+2 = 0

8(1/8) - a(1/4) -1/2 +2 = 0

1 -a/4 -1/2 +2 = 0

4-a-4+8/4 = 0

-a+8 = 0

a = 8