Question

If x=1/2 is a zero of (x)=8x^3 +ax^2 -4 x+2 find the value of a​

Answer 1

Step-by-step explanation:

p(x)=8x^3 +ax^2 -4 x+2

p(½)=8X(½)³ +aX(½)² -4X(½)+2

0 = 8X⅛ +aX¼ - 2 + 2

0 = 1 + a/4

-1 = a/4

or,

a = -4

Answer 2

Answer:

$x = \frac{ 1}{2} \\ \\ 8 {x}^{3} + a {x}^{2} - 4x + 2 = 0 \\ \\ 8 \frac{1}{8} + a \frac{1}{4} - 4 \frac{1}{2} + 2 = 0 \\ \\ 1 + \frac{a}{4} - 2 + 2 = 0 \\ \\ 1 + \frac{a}{4} = 0 \\ \\ \frac{4 + a}{4} = 0 \\ \\ 4 + a = 0 \\ \\ a = - 4$